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Answer:
68.27%.
Step-by-step explanation:
Here we have [tex]\mu=500,\sigma=100[/tex]
Let X shows the SAT score. z-score for X=400 is
[tex]z=\frac{X-\mu}{\sigma}=\frac{400-500}{100}= -1[/tex]
z-score for X=600 is
[tex]z=\frac{X-\mu}{\sigma}=\frac{600-500}{100}=1[/tex]
So the proportion of SAT scores falls between 400 and 600 is
[tex]P(400<X<600)=P(-1<z<1)=0.6827[/tex]
hence, required percentage is 68.27%.
one can use the same method to find the% for all other cases as
well.