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Answer:
Cost is G for t hours =[tex]\left \{ {5t for{t=0 <t<2} \atop 12 for{t >2}} \right.[/tex]
Step-by-step explanation:
According to question parking garage takes
5$ for 0 to 1hr
10$ for 0 to 2hr and
12$ for 0 to 24hr
Let t be the time for which car is parked in garage and the total cost is G then
G =[tex]\left \{ {5t for{t=0 <t<2} \atop 12 for{t >2}} \right.[/tex]
therefore cost is G =[tex]\left \{ {5t for{t=0 <t<2} \atop 12 for{t >2}} \right.[/tex]
The cost of parking a car for 5 hours is required.
Cost of 5 hours will be $25.
The cost of parking for each hour = $5
The cost of parking for entire day = $120
Let [tex]t[/tex] be the number of hours
[tex]G[/tex] be the total cost.
The function will be
[tex]G(t)=5t[/tex]
The cost at 5 hours will be
[tex]G(5)=5\times 5=25[/tex]
So, cost of 5 hours will be $25.
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