Selgamil320idn
Answered

IDNLearn.com: Where your questions meet expert advice and community insights. Find the solutions you need quickly and accurately with help from our knowledgeable community.

Can you please help me

Can You Please Help Me class=

Sagot :

Answer:

In ΔECD

<E = <C = <D

using angle sum property of triangle

<E + <C + <D = 180°

<E + <E + <E = 180° ( As <E = <C = <D )

3<E = 180

<E = 60°

NOW

<BCA + <ACE + <ECD = 180 (L. P. A.)

50° + <ACE + 60° =180

110 + <ACE = 180

<ACE = 70°

NOW as

AC = AE

So using property of triangle that angle opposite to equal sides are equal we get

<ACE = <AEC = 70°

In triangle ΔAEC

Now using Angle sum property of triangle

<ACE + <AEC + <CAE = 180°

70° + 70° + x = 180

140 + x = 180

x = 40°

Now in ΔABC

AB = AC

using property of triangle that angle opposite to equal sides are equal

So <ACB = <ABC = 50°

Now using angle sum property of triangle in ΔABC

<ACB + <ABC + <CAB = 180

50 + 50 + y = 180

100 + y = 180

y = 80°

so x = 40° and y = 80°

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.