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Sagot :
Answer:
41.81 ; 12.67
Step-by-step explanation:
Given the data:
Age range, years 18-28 29-39 40-50 51-61 62 and over
Midpoint x 23 34 45 56 67
Percent of super shoppers 9% 46% 22% 11% 12%
Midpoint, x : 23 34 45 56 67
Frequency, f : 0.09_ 0.46 _ 0.22 __0.11 __ 0.12
The mean(m)
Σfx / Σf
[(23 * 0.09) + (34 * 0.46) + (45 * 0.22) + (56 * 0.11) + (67 * 0.12)] / (0.09 + 0.46 + 0.22 + 0.11 + 0.12)
= 41.81 / 1
Mean = 41.81
Standard deviation :
Sqrt[(Σ(X² * f) / Σf) - m²)]
((23^2*0.09) + (34^2*0.46) + (45^2*0.22) + (56^2*0.11) + (67^2*0.12)) / 1
1908.51 - 41.81^2
Sqrt(160.4339)
= 12.666250
= 12.67
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