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What is the theoretical yield, in grams, and the percent yield of a reaction of 3.0 moles of two hydrogen atoms and 2.0 moles of Iodine atoms to produce one mole of Hydrogen Iodine.

Sagot :

Manethoidn

Answer:

512g, 25%

Explanation:

H_2+I_2→ 2HI

3 moles H_2× 2moles HI/1 mole of H_2= 6 moles of HI

2moles I_2×2 moles of HI/1 mole of I_2= 4 moles of HI

Now, theoretical yield of HI = 4 moles ×128 g/ mole = 512 g

percentage yield = (128g/512g)×100 = 25%

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