Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Get prompt and accurate answers to your questions from our experts who are always ready to help.

Consider functions fand g.
f(x) = -13
g(x) = |1/8x-1|


Consider Functions Fand G Fx 13 Gx 18x1 class=

Sagot :

Answer:

We conclude that

(g o f) (4) = 9

Hence, option C is correct.

Step-by-step explanation:

Given

f(x) = -x³

g(x) = |1/8x - 1|

To determine

(g o f) (4) = ?

Using the formula

(g o f) (4) = g[(f(4)]

first we need to determine f(4)

so substituting x = 4 into f(x) = -x³

f(x) = -x³

f(4) = -(4)³ = -64

so

(g o f) (4) = g[(f(4)] = g(-64)

so substitute x = -64 in g(x) = |1/8x - 1|

[tex]g\left(x\right)=\left|\frac{1}{8}x-1\right|[/tex]

substitute x = -64

[tex]g\left(-64\right)=\left|\frac{1}{8}\left(-64\right)-1\right|[/tex]

            [tex]=\left|-\frac{1}{8}\cdot \:64-1\right|[/tex]

            [tex]=\left|-8-1\right|[/tex]

            [tex]=\left|-9\right|[/tex]

Apply absolute rule: |-a| = a

            [tex]=9[/tex]

Therefore, we conclude that

(g o f) (4) = 9

Hence, option C is correct.