Answered

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Line q passes through the points (4, 6) and (0, 6). What is the equation for the line which is perpendicular to q and passes through the point (–2, 3)?

Sagot :

Unicorn3125idn

Answer:

        x = -2

Step-by-step explanation:

The slope of q:  

                       [tex]m_q=\dfrac{6-6}{4-6}=0[/tex]

It means the line q is parallel to X-axis. Therefore any line perpendicular to q is parallel to Y-axis.

Any line parallel to Y-axis is:  x = x₀, where x₀ is the x-coordinate of any point the line passing through.

(-2, 3)    ⇒   x₀ = -2

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