Answer:
first choice: y≥1/3 x+3 and 3x-y>2
Step-by-step explanation:
The system of linear inequalities is: [tex]y \ge \frac{1}{3}x + 3[/tex] and [tex]3x -y > 2[/tex]
The equation of the orange line is calculated using:
[tex]y = \frac{y_2 - y_1}{x_2-x_1} \times (x -x_1) + y_1[/tex]
This gives
[tex]y = \frac{3- 4}{0-3} \times (x -3) + 4[/tex]
[tex]y = \frac{- 1}{-3} \times (x -3) + 4[/tex]
[tex]y = \frac{1}{3} \times (x -3) + 4[/tex]
Open the bracket
[tex]y = \frac{1}{3}x -1 + 4[/tex]
[tex]y = \frac{1}{3}x + 3[/tex]
The inequality has a thick line, and the upper region is shaded.
So, the inequality is:
[tex]y \ge \frac{1}{3}x + 3[/tex]
The equation of the gray line is calculated using:
[tex]y = \frac{y_2 - y_1}{x_2-x_1} \times (x -x_1) + y_1[/tex]
This gives
[tex]y = \frac{4- 1}{2-1} \times (x -1) + 1[/tex]
[tex]y = \frac{3}{1} \times (x -1) + 1[/tex]
[tex]y = 3 \times (x -1) + 1[/tex]
Open the bracket
[tex]y = 3x -3 + 1[/tex]
[tex]y = 3x -2[/tex]
The inequality has a dotted line, and the right region is shaded.
So, the inequality is:
[tex]y < 3x -2[/tex]
Rewrite as:
[tex]3x -2 > y[/tex]
So, we have:
[tex]3x -y > 2[/tex]
Hence, the system of linear inequalities is:
[tex]y \ge \frac{1}{3}x + 3[/tex] and [tex]3x -y > 2[/tex]
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