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CAN SOMEONE PLS HELP WITH THIS ASAP

CAN SOMEONE PLS HELP WITH THIS ASAP class=

Sagot :

Rebeccarayshmaidn

Answer:

the second option

Step-by-step explanation:

[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]

[tex] \cos(theta) = \frac{adjacent}{hypotenuse} [/tex]

[tex] \tan(theta) = \frac{opposite}{adjacent} [/tex]

theta = 45°

hypotenuse = 9

opposite = x

find x using the sin formula

[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]

[tex] \sin(45) = \frac{x}{9} [/tex]

[tex] \sin(45) \times 9 = x[/tex]

[tex] \frac{9 \sqrt{2} }{2} = x[/tex]

[tex]x = \frac{9 \sqrt{2} }{2} [/tex]

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