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Sagot :

Answer:

4) yes, the rate is 3

5) no

6) yes, the rate is 5

Step-by-step explanation:

Direct variation is y = kx.

4.

First, substitute your values into the equation for direct variation to find K, the rate.

3 = k(1)

3 = k

Now let's see if this holds true.

6 = 3(2)

6 = 6

This looks true, but let's do another one from the table.

9 = 3(3)

9 = 9

And another just to check.

12 = 3(4)

12 = 12

So, #4 is direct variation.

5.

1 = k(2)

1/2 = k

Let's test for all of the other values to be sure.

2 = (1/2)(3)

2 ≠ 1.5

3 = (1/2)(4)

3 ≠ 2

This is not true. #5 is not an example of direct variation.

6.

5 = k(1)

5 = k

Time to check.

10 = 5(2)

10 = 10

Again.

15 = 5(3)

15 = 15

Again.

20 = 5(4)

20 = 20

One last time...

25 = 5(5)

25 = 25

#6 is an example of direct variation.

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