Answered

Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

Determine the center and radius of the following circle equation: x^2+y^2-14x+4y+52=0 x 2 +y 2 −14x+4y+52=0

Sagot :

ChoiSungHyunidn

Step-by-step explanation:

x² + y² - 14x + 4y + 52 = 0

(x - 7)² - 49 + (y + 2)² - 4 + 52 = 0

(x - 7)² + (y + 2)² = 1

Hence the circle's center is (7, -2) and the radius is 1.

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.