Find the best answers to your questions with the help of IDNLearn.com's expert contributors. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.

A combination lock has 7 digits. How many distinct combinations does this lock have if the numbers used have to be 0 through 5

Sagot :

Answer:

279,936

Step-by-step explanation:

Since there are 6 options for every digit, and seven digits

So,

6^7=279,936

The total number of  distinct combinations for making 7 digits lock is 2,79,936.

What is permutation?

A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters.

Formula for permutation with repetition:

[tex]nP_{r} =n^{r}[/tex]

Where,

P is the total number of combinations.

n is the total number of items in a set

r is the total number of items to be selected from the set

According to the given question.

We have to form a lock that has 7 digits by using numbers from 0 to 5.

Total numbers of items in a set = 6

and total number of items to be selected = 7

Since, we have to form a lock of 7digits but we have only 6 digits. So we have to repeat this numbers so that we can form a 7 digit lock.

Therefore, the total number of combinations for making 7 digits lock is given by

[tex]6P_{7} = 6^{7}[/tex]

⇒[tex]6^{7}=2,79,936[/tex]

Hence, the total number of  distinct combinations for making 7 digits lock is 2,79,936.

Find out more information about combination and permutation here:

https://brainly.com/question/13387529

#SPJ2

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.