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find the consecutive even integers such that three times the larger number is 30 more than the smaller one. help :')

Sagot :

Abidemiokinidn

Answer:

12 and 14

Step-by-step explanation:

Let the even integers be x and x+2

three times the larger number is expressed as 3(x+2)

30 more than the smaller one is x + 30

Equating both expressions

3(x+2) = x +30

Find x

3x+6 = x+30

3x-x = 30-6

2x = 24

x = 12

The second integer is 12+2 = 14

Hence the required integers are 12 and 14

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