Answered

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Given: in a right triangle, cot0 = 28/45
1. what is csc0
2. what is sec0

Sagot :

Answer:

i)    [tex]cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}[/tex]

ii)   [tex]sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}[/tex]

Step-by-step explanation:

Step(i):-

Given that    

                 [tex]cot 0 = \frac{28}{45} = \frac{adjacentside}{opposite side}[/tex]

Hypotenuse AC² = AB²+BC²

    ⇒             AC² = 45²+28² = 2809

   ⇒             AC = √2809

 ⇒              AC = 53

Hypotenuse  AC =53

Step(ii):-

i)    [tex]cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}[/tex]

ii)   [tex]sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}[/tex]

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