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Sagot :
Answer:
a. Yes, because the acceleration of the crate is 2.0 m/s².
Explanation:
Given
[tex]Force = 6N[/tex] --- f
[tex]Mass = 3kg[/tex] --- m
[tex]Time = 1.5s[/tex] --- t
[tex]Velocity = 3.0m/s[/tex] --- v
Required
Does the system support [tex]F=ma[/tex]
Yes, it does and this is shown below
The crate is initially at rest; so:
[tex]u = 0[/tex]
Using the first equation of motion
[tex]v = u + at[/tex]
Substitute values for v, u and t
[tex]3 = 0 + a*1.5[/tex]
[tex]3 = 1.5a[/tex]
Make a the subject
[tex]a = 3/1.5[/tex]
[tex]a = 2[/tex]
Using [tex]F = ma[/tex]
Substitute values for F and m
[tex]6 = 3 * a[/tex]
Divide both sides by 3
[tex]6/3 = 3/3 * a[/tex]
[tex]2 = a[/tex]
[tex]a = 2[/tex]
In both cases:
[tex]a = 2[/tex]
Hence, option (a) is correct.
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