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Thuy wrote the system of equations. 24 x + 36 y = 72. Negative 16 x + 8 y = 80. If the second equation is multiplied by 3, what should the first equation be multiplied by to eliminate the x variable by addition?

Sagot :

Answer:

multiply the first equation by 2

Step-by-step explanation:

24x + 36y = 72

-16x + 8y = 80

48x + 72y = 144

-48x + 24y = 240

96y = 384

y = 4

24x + 36(4) = 72

24x + 144 = 72

24x = -72

x = -3

(-3, 4)

First equation should be multiplied by 2 to eliminate the x variable by addition.

What is the system of equation?

" A system of equation is a finite set of equations for which we find the common solution."

According to the question,

System of equations are

24x + 36y = 72

-16x + 8y = 80

As per the given condition,

Second equation multiply by 3 we get,

-48x + 24y =240

To eliminate x by adding we have to multiply  first equation by 2 we get,

48x + 72y = 144

 Now add both the equation we get,

    96y =384

⇒ y = 4

Hence, first equation should be multiplied by 2 to eliminate the x variable by addition.

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