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Fe0 + 2H+1 Cl-1 → Fe+2 Cl2 -1 + H20 ↑
De acuerdo con la ecuación planteada si se cambia el hierro Fe por dos moles de sodio Na0 probablemente formará
A. 2NaCl + H2
B. NaCl + H2
C. 2NaH + Cl2
D. NaCl2 + H2
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