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Sagot :
Answer:
Mass = 82.11 g
Explanation:
Given data:
Mass of KCl = 50.0 g
Mass of O₂ = 50.0 g
Mass of KClO₃ produced = ?
Solution:
Chemical equation:
2KCl + 3O₂ → 2KClO₃
Number of moles of KCl:
Number of moles = mass /molar mass
Number of moles = 50.0 g/ 74.5 g/mol
Number of moles = 0.67 mol
Number of moles of O₂:
Number of moles = mass /molar mass
Number of moles = 50.0 g/ 32 g/mol
Number of moles = 1.56 mol
Now we will compare the moles of oxygen and KCl.
O₂ : KClO₃
3 : 2
1.56 : 2/3×1.56 = 1.04 mol
KCl : KClO₃
2 : 2
0.67 : 0.67
Number of moles of KClO₃ formed by KCl are less thus, it will act as limiting reactant.
Mass of KClO₃:
Mass = number of moles × molar mass
Mass = 0.67 mol ×122.55 g/mol
Mass = 82.11 g
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