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Sagot :
The theoretical yield : = 10.251 g
Further explanation
Given
Reaction
3H₂(g)+N₂(g)→2NH₃(g)
1.81 g H₂
10.2 g N₂
2.19 g NH₃
Required
The theoretical yield
Solution
Find limiting reactant :
H₂ : 1.81 g : 2 g/mol = 0.905 mol
N₂ : 10.2 g : 28 g/mol = 0.364 mol
mol : coefficient
H₂ = 0.905 : 3 = 0.302
N₂ = 0.364 : 1 = 0.364
H₂ as a limiting reactant(smaller ratio)
Moles NH₃ based on H₂, so mol NH₃ :
= 2/3 x mol H₂
= 2/3 x 0.905
=0.603
Mass NH₃ :
= mol x MW
=0.603 x 17 g/mol
= 10.251 g
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