Answered

IDNLearn.com is your go-to resource for finding answers to any question you have. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

ALGEBRA II // MODULE 1
FUNCTIONS AND INVERSES - 1.2
1.2
READY, SET, GO!
Name
Period
Date
READY
Topic: Solving for a variable
Solve for x.
1.
17 = 5x + 2
2. 2x² – 5 = 3x2 – 12x +
31
3. 11 = 2x + 1

Sagot :

Answer:

1. x = 3

2.x = 6

3. x = 5

I hope this helps you :D

MrRoyalidn

To solve for variables, we start by isolating the variable term and then solve for the variable. The values of x in the given equations are 3, 6 and 5, respectively.

Equation (1)

[tex]17 = 5x + 2[/tex]

Collect like terms

[tex]5x = 17 -2[/tex]

[tex]5x = 15[/tex]

Divide both sides by 5

[tex]x =3[/tex]

Equation (2)

[tex]2x^2 - 5 = 3x^2 - 12x + 31[/tex]

Collect like terms

[tex]3x^2 - 2x^2 - 12x + 31 +5=0[/tex]

[tex]x^2 - 12x + 36=0[/tex]

Expand

[tex]x^2 - 6x - 6x + 36=0[/tex]

Factorize

[tex]x(x - 6) - 6(x -6)=0[/tex]

Factor out x - 6

[tex](x - 6)(x -6)=0[/tex]

This means that:

[tex]x -6=0[/tex]

Solve for x

[tex]x = 6[/tex]

Equation (3):

[tex]11 = 2x + 1[/tex]

Collect like terms

[tex]2x = 11-1[/tex]

[tex]2x = 10[/tex]

Divide both sides by 2

[tex]x =5[/tex]

Hence, the values of x in the given equations are 3, 6 and 5.

Read more about equations at:

https://brainly.com/question/953809

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.