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2AlCl3 + 2Al + 3Cl2
If 20.0 g of aluminum chloride are decomposed, how many molecules of chlorine gas are produced?
A )6.63 x 1022 molecules CI
B )2.70 x 1023 molecules Cl2
C )1.35 x 1023 molecules Cl2
D )9.42 x 1023 molecules Cl2

Sagot :

ChoiSungHyunidn

Explanation:

Molar mass of AlCl3 = 133.34g/mol

Moles of AlCl3 used

= 20.0g / (133.34g/mol) = 0.150mol

Mole Ratio of AlCl3 to Cl2 = 2 : 3,

Moles of Cl2 produced

= 0.150mol * (3/2) = 0.225mol

We know that 1 mole of any gas has

6.023 * 10²³ molecules.

Hence, number of molecules in Cl2

= 0.225mol * (6.023 * 10²³/mol)

= 1.35 * 10²³ molecules. (C)

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