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Answer:167.9 g Ag
Explanation: 1 mol Cu + 2 mol AgNO3 = 2 mol Ag + 1 mol Cu(NO3)2
63.55 g Cu —> 2*107.688 g Ag
So 49.1 g Cu —> (49.1/63.55)*2*107.688 = 167.9 g Ag