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Sagot :
Answer:
probability that a rivet is defective is 0.00868
Step-by-step explanation:
given data
rivets = 20
all seam need reworking P = 16% = 0.16
solution
we consider here probability of a defective rivet = p
and 0.16 = P [Seam needs reworking) = P (at least one rivet in the seam is defective)
so that for non-defective = 1 - P [all the rivets are non-defective]
and that will be here as = 1 - P [rivet 1 is non-defective, rivet 2 is non-defective, rivet 3 is non-defective,...............,rivet 20 is non-defective]
= [tex]1 - (p})^{20}[/tex] ....................1
so
1-0.16 = [tex]1 - (p})^{20}[/tex]
0.84 = [tex]1 - (p})^{20}[/tex]
[tex]0.84^{\frac{1}{20}}[/tex] = 1 - p
solve it we get
p = 0.00868
so, probability that a rivet is defective is 0.00868
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