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Sagot :
The equation that represents a line with a slope of -6/5 and a y-intercept of 1 is y = -6/5x + 1
How to determine the equation?
The given parameters are:
- Slope, m = -6/5
- y-intercept = 1
Let the variable of the equation be x.
A linear equation is represented as:
y = Slope * x + y-intercept
So, we have:
y = -6/5 * x + 1
Evaluate
y = -6/5x + 1
Hence, the equation is y = -6/5x + 1
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