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Answered

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Find the zeros of 6x^2-27x

Sagot :

WisdomPearlidn

Answer:

x = 0, 9/2

Step-by-step explanation:

6x^2 - 27x = 0 (original)

3x(2x - 9) = 0 (factor out GCF of 3x)

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(solve each factor (3x and 2x - 9) for x)

3x = 0

x = 0

2x - 9 = 0

2x = 9

x = 9/2

Jasongarciia619idn
x=9/2 is correct how wisdom said
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