IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.

a) What magnitude point charge creates a 12596.37 N/C electric
held at a distance of 0.593 m?


Sagot :

Answer:

[tex]Q = 4.9216 * 10^{-7}C[/tex]

Explanation:

Given

[tex]E = 12596.37 N/C[/tex]

[tex]r = 0.593m[/tex]

Required

Determine the magnitude point charge (Q)

This question will be solved using [tex]the\ magnitude[/tex] of the electric field formula

[tex]E = \frac{kQ}{r^2}[/tex]

Where

[tex]k = 9 * 10^9\ Nm^2 / C^2[/tex]

Make Q the subject in [tex]E = \frac{kQ}{r^2}[/tex]

[tex]E * r^2 = kQ[/tex]

[tex]Q = \frac{E * r^2}{k}[/tex]

Substitute values for E, r and k

[tex]Q = \frac{12596.37 * 0.593^2}{9 * 10^9}[/tex]

[tex]Q = \frac{4429.50}{9 * 10^9}[/tex]

[tex]Q = \frac{492.16}{10^9}[/tex]

[tex]Q = 492.16 * 10^{-9}[/tex]

Express in standard form

[tex]Q = 4.9216 * 10^2 * 10^{-9}[/tex]

[tex]Q = 4.9216 * 10^{2-9}[/tex]

[tex]Q = 4.9216 * 10^{-7}C[/tex]