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Sagot :
Answer:7
Step-by-step explanation:
This question is on the ukmt junior maths challenge which I'm doing now, out of the options given I got 7, because 2+4+6+5+(5×20)+(7×7)= 166, (then dividing that by the number of numbers to get the mean) so 166÷31= 5.354.....
Also the 3 has a recurring symbol above it
The 7 is times seven so uh yeah<3
The smallest possible value of 'q' is 7 and this can be determined by using the hit and trial method and mean formula.
Given :
- Sam writes on a whiteboard the positive integers from 1 to 6 inclusive once each. she then writes p additional fives and q sevens on the board.
- The mean of all the numbers on the board is then 5.3.
The following steps can be used in order to determine the smallest possible value of q:
Step 1 - The formula of the mean can be used in order to determine the smallest possible value of q.
Step 2 - The mean of all the numbers is given by:
[tex]\rm \dfrac{2+4+6+5+5p+7q}{6+p+q}=5.3[/tex]
[tex]\rm \dfrac{21 + 5p + 7 q}{6+p+q} = 5.3[/tex]
Step 3 - So, by the hit and trial method, the value of q can be determined.
Therefore, the value of 'q' is 7.
For more information, refer to the link given below:
https://brainly.com/question/25277954
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