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The sum of all the solutions of the equation (6x+k)(3x-11)=0 is 1. Find K

BRANLIEST PLUS 20 POINTS

Sagot :

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Answer:

16

Step-by-step explanation:

6x+k = 0

x = -k/6

3x-11 = 0

x = 11/3

-k/6 + 11/3 = 1

k - 22 = -6

k = 16

The value of k is "8".

Find K:

[tex](6x+k)(3x-11)=0\ \ is \ \ 1 \\\\K=?[/tex]

[tex]\to (6x+k)(3x-11)=0 \ \ is \ \ 1 \\\\\to (6x+k)=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ (3x-11)=0\\\\\to 6x=-k\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x=11\\\\\to x=-\frac{k}{6}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{11}{3}\\\\[/tex]

[tex]\to - \frac{k}{6}+ \frac{11}{3}=1\\\\\to \frac{-2k+ 22}{6}=1\\\\\to -2k+ 22=6\\\\\to -2k =6-22\\\\\to -2k =-16\\\\\to k=\frac{16}{2}\\\\\to k=8[/tex]

Therefore, the final value of k is "8".

Learn more about the find k here:

brainly.com/question/20041760

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