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Answered

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When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards? (Unit = m/s)

When A Golf Club Hits A 00459 Kg Ball At Rest It Exerts A 2380 N Force For 000100 S What Is The Speed Of The Ball Afterwards Unit Ms class=

Sagot :

QuasarJoseidn

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x [tex]\frac{v - u}{t}[/tex]  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x [tex]\frac{v- 0}{0.001}[/tex]  

        0.0459v  = 2.38

                   v = 51.85m/s

Answer:

2.38

Explanation:

F = dp/dt  --> dp = F*dt ---> p = F*t if F is constant over time so

p = 2380N* 0.001 s = 2.38 kg-m/s

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