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If the nth term of a number sequence is n^2+4
find the first 3 terms and the 10th term.​

Sagot :

Answer:

a) The sequence of first three terms

5 , 8 , 13 ..

b) The [tex]10^{th}[/tex] of the sequence

a₁₀ = 104

Step-by-step explanation:

Step(i):-

Given [tex]n^{th}[/tex] term of the sequence

  aₙ = n² + 4

put n=1

First term  a₁ = 1² +4 = 1+5

put n =2

Second term a₂ = 2²+4 = 4+4 =8

Put n=3

Third term a₃ = 3² +4 = 9+4 =13

The sequence of first terms

5 , 8 , 13 ..

Step(ii):-

Given [tex]n^{th}[/tex] term of the sequence

  aₙ = n² + 4

put n =10

a₁₀ = 10²+4 = 100+4 = 104

a₁₀ = 104

The [tex]10^{th}[/tex] of the sequence

a₁₀ = 104

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