IDNLearn.com provides a comprehensive platform for finding accurate answers. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.
Mass of KCl : 32 g
Given
Reaction
2KCIO₃ → 2KCI + 30₂
52 g Potassium chlorate
Required
Mass of KCl
Solution
mol of KCIO₃ :
= mass : MW
= 52 g : 122.55 g/mol
= 0.424
From equation, mol KCl :
= 2/2 x mol KCIO₃
= 2/2 x 0.424
= 0.424
Mass KCl :
= mol x MW
= 0.424 x 74.5513 g/mol
= 31.6≈32 g