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Note: I am assuming the first equation is:
x+y = 3
Answer:
The solution to the system of equations is:
(x, y) = (-2, 36)
Therefore, the x-coordinate of the solution of the system
x = -2
Step-by-step explanation:
Given the system of equations
[tex]\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}[/tex]
subtracting the equations
[tex]x-y=-38[/tex]
[tex]-[/tex]
[tex]\underline{x+y=34}[/tex]
[tex]-2y=-72[/tex]
solve -2y for y
[tex]-2y=-72[/tex]
Divide both sides by -2
[tex]\frac{-2y}{-2}=\frac{-72}{-2}[/tex]
[tex]y=36[/tex]
For x+y=34 plug in y = 36
[tex]x+36=34[/tex]
Subtract 36 from both sides
[tex]x+36-36=34-36[/tex]
Simplify
[tex]x=-2[/tex]
Thus, the solution to the system of equations is:
(x, y) = (-2, 36)
Therefore, the x-coordinate of the solution of the system
x = -2