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A 40-N force acts on an 80-kg object, initially moving at 20 m/s. How far will the object travel in the next five seconds?

Sagot :

Answer:

106.25 m

Explanation:

Acceleration a = force / mass

= 40 / 80 = 0.5 m /s²

initial velocity u = 20 m /s

a = 0.5 m /s²

time t = 5 s

displacement s = ?

s = ut + 1/2 a t²

= 20 x 5 + .5 x .5 x 5²

= 100 + 6.25

= 106.25 m .

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