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What is the avergae dilration rate per minute?

Sagot :

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Answer:

1.023 * 106 * 5 = 5.115 * 106cfm       (K assumed as 5)

Explanation: Q’ = (403 * 106 * SG * ER) / (MW * C)

where Q’ is effective flow rate in cfm,

         SG is specific gravity,

         ER is emission rate in pints/min,

         MW is molecular weight,

         C is concentration in ppm.

Actual flow rate Q = Q’ * K      where K is the factor for incomplete mixing(1 ≤ K ≤ 10)

For methyl chloride, SG = 1.785, MW = 50.49

Given:- ER = 0.24 cfm = 0.24 * 59.85 pints/min = 14.36 pints/min

            C = 200 ppm

Q’ = (403 * 106 * 1.785 * 14.36) / (50.49 * 200) = 1.023 * 106 cfm

Q = 1.023 * 106 * 5 = 5.115 * 106cfm       (K assumed as 5)

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