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The graph of a line on a coordinate plane has a slope of 12 and passes through the point (4,−3). What equation describes the line?

Sagot :

Answer:

y =12x -51

Step-by-step explanation:

slope = (y-y') / (x-x')

12 = (y- -3) / (x-4) = (y+3) / (x-4)

12*(x-4) = y+3

12x -48 = y+3

y =12x -51

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