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PLEASE HELP ASAP!!! THIS IS MY LAST QUESTION!! SHOW WORK

PLEASE HELP ASAP THIS IS MY LAST QUESTION SHOW WORK class=

Sagot :

Step-by-step explanation:

We have to find (x³ - 5x² - 12x + 36)/(x - 6).

You can do this by the following methods:

  • Long Division,
  • Synthetic Division, or
  • Comparing Coefficients

I have chosen to do by Comparing Coefficients.

x³ - 5x² - 12x + 36

= (x - 6)(Ax² + Bx + C)

= Ax³ + (B - 6A)x² + (C - 6B)x - 6C.

By Comparing Coefficients, we have:

  • A = 1,
  • B - 6A = -5,
  • C - 6B = -12, and
  • -6C = 36.

Solving them we have A = 1, B = 1, C = -6.

Therefore x³ - 5x² - 12x + 36

= (x - 6)(x² + x - 6)

= (x - 6)(x + 3)(x - 2).

Hence the other 2 dimensions are

(x + 3) and (x - 2).