Answered

IDNLearn.com offers expert insights and community wisdom to answer your queries. Join our community to receive timely and reliable responses to your questions from knowledgeable professionals.

I need help for this.
A line has gradient 6 and passes through the points with coordinates (-1,6) and (7,a). Find the value of a

Sagot :

Luanaidn
[tex]General\ formula\ for\ line:\\\\y=ax+b,\ where\ a-gradient\\\\y=6x+b\\\\Substitute\ point\ (-1,6):\\\\6=6\cdot(-1)+b\\6=-6+b\\b=6+6\\b=12\\\\y=6x+12\\\\Substitute\ point\ (7,a)\\\\a=6\cdot7+12\\a=42+12=54[/tex]
Olemakpaduidn
We can also see it this way: 

Noting that point in the form  (x, y)
(-1, 6)  and (7, a) .  x1 = -1, y1 = 6,  x2 = 7, y2 = a
Gradient , m =  (y2- y1) / (x2 - x1).  m =6.
Substituting:

6 =  (a - 6) / (7 - -1)
6 =  (a -6) / (7+1)
6 = (a -6) /8    Cross Multiplying
48 = a -6.
48 +6 = a.
54 = a.
Therefore a = 54.
I hope this helps.

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.