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A line contains the points (4, 2) and (0, -1). What is the equation of the line?
D
y = 2x - 6
B
3
y = = X - 1
4
С
1
y = =X+ 1
4
D
4
-X
3
10

Sagot :

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Answer:

y=3/4x-1 or 4y+-3x=-4

Step-by-step explanation:

If the line is (4,2) and (0,-1) then you have to first find the slope (rise-over-run) which is 3/4. The y-intercept is -1.

y=mx+b

Slope-Intercept Form:

y=(slope)x+(y-intercept)

so,

y=(3/4)x-1

Standard Form:

4y+-3x=-4

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