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Sagot :
Volume of each solution : 60 ml 20% and 40 ml 45%
Further explanation
Given
20% and 45% acid
100 ml of 30% acid
Required
Volume of each solution
Solution
Molarity from 2 solutions :
Vm Mm = V₁. M₁ + V₂. M₂
m = mixed solution
V = volume
M = molarity
V₁ = x ml
V₂ = (100 - x) ml
Input the value :
100 . 0.3 = x . 0.2 + (100-x) . 0.45
30 = 0.2x+45-0.45x
0.25x=15
x= 60 ml
V₁ = 60 ml
V₂ = 100 - 60 = 40 ml
For the preparation of the 30% 100 ml acid solution, 40 ml 45% solution has been mixed with 60 ml 20% acid solution.
To prepare the solution with the concentrated solution:
MV = M1V1 + M2V2
The M has been the concentration of the resulted solution, and V has been the volume of the resulting solution.
M1 and M2 and V1 and V2 have been the concentration and volume of the given solution.
0.30 × 100 ml = 0.20 × x + 0.45 × (100 - x)
30 = 0.20x + 45 - 0.45x
0.45x - 0.20x = 45 - 30
0.25x = 15
x = 60 ml
The volume of 20% solution has been x = 60 ml
The volume of 45% solution has been 100 - x = 40 ml.
For the preparation of the 30% 100 ml acid solution, 40ml 45% solution has been mixed with 60ml 20% acid solution.
For more information about the acid preparation, refer to the link:
https://brainly.com/question/1457002
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