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Answer:
See the answers below.
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}-a*t[/tex]
where:
Vf = final velocity = 10 [m/s]
Vo = initial velocity = 40 [m/s]
t = time = 5 [s]
a = acceleration [m/s²]
Now replacing:
[tex]10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}][/tex]
Note: The negative sign in the above equation means that the velecity is decreasing.
2)
To solve this second part we must use the following equation of kinematics.
[tex]v_{f}^{2} =v_{o}^{2} -2*a*x\\[/tex]
where:
x = distance [m]
[tex](10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m][/tex]