Join the IDNLearn.com community and start finding the answers you need today. Get accurate and comprehensive answers from our network of experienced professionals.
Sagot :
Answer:
The spring constant is k=7031.25
Explanation:
We start by using the conservation of mechanical energy:
Ui + Ki = Uf + Kf
the Ui (initial potential energy) is zero since the spring is relaxed.
In the final situation, the Kf (final kinetic energy is zero since the car and spring are NOT in motion)
Then we have:
[tex]K_i=U_f\\\frac{1}{2} m*v^2=\frac{1}{2} k*(\Delta x)^2\\\frac{1}{2} 2000*15^2=\frac{1}{2} k*(8)^2\\k=7031.25[/tex]
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.