Yuyubullyme21idn
Answered

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What are the vertex and axis of symmetry of the parabola y = x2 – 16x + 63?

Sagot :

Reidlucidn

Answer:

-23

Step-by-step explanation:

Cetaceaidn

Vertex is = (8, -1)

Axis of symmetry : x = 8

We first write the given equation in vertex form.

[tex]y=x^{2} -16x+63\\y=x^2-2(8)x+64-1\\y=(x^2-2(8)x+8^2)-1\\y=(x-8)^2-1[/tex]

Compare it with [tex]y=a(x-h)^2+k[/tex].

So vertex= (h, k) = (8, -1).

Axis of symmetry passes through the vertex and parallel to the y-axis.

So the equation of the axis of symmetry is x = 8.

Learn more: https://brainly.com/question/9201543

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