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13) Find two consecutive positive integers such that the square of the smaller increased by 4 times the
larger is 64

Sagot :

Safele1149idn

Answer:

LET X & (X+1) BE THE 2 INTEGERS.

X^2+4(X+1)=64

X^2+4X+4-64=0

X^2+4X-60=0

(X-6)(X+10)=0

X-6=0

X=6 ANS.FOR THE SMALLER INTEGER.

6+1=7 ANS. FOR THE LARGER INTEGER.

PROOF:

6^2+4*7=64

36+28=64

64=64

Step-by-step explanation:

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