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How many atoms are in a 158.69 g sample of nickel?

Sagot :

Spaceidn

Answer:

1.6283 × 10²⁴ atoms Ni

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Use Dimensional Analysis

Explanation:

Step 1: Define

158.69 g Ni

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

Step 3: Convert

  1. Set up:                      [tex]\displaystyle 158.69 \ g \ Ni(\frac{1 \ mol \ Ni}{58.69 \ g \ Ni})(\frac{6.022 \cdot 10^{23} \ atoms \ Ni}{1 \ mol \ Ni})[/tex]
  2. Multiply/Divide:        [tex]\displaystyle 1.62827 \cdot 10^{24} \ atoms \ Ni[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 5 sig figs.

1.62827 × 10²⁴ atoms Ni ≈ 1.6283 × 10²⁴ atoms Ni

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