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2 Na + Cl2 --> 2 NaCl
If 15 mol Na reacts with 15 mol Cl2, what is the theoretical yield of NaCl that could be
formed?

Sagot :

Neetooidn

Answer:

Theoretical yield of NaCl = 877.5 g or 15 moles

Explanation:

Given data:

Number of moles of Na = 15 mol

Number of moles of Cl₂ = 15 mol

Theoretical yield of NaCl = ?

Solution:

Chemical equation:

2Na + Cl₂      →     2NaCl

Now we will compare the moles of Na and Cl₂ with NaCl.

                Cl₂       :        NaCl

                 1          :          2

               15          :         2/1×15 = 30 mol

                Na       :        NaCl

                 2          :          2

               15          :          15

Less number of NaCl are produced by Na it will act as limiting reactant.

Theoretical yield:

Mass = number of moles × molar mass

Mass = 15 mol × 58.5 g/mol

Mass = 877.5 g

               

The theoretical yield of NaCl that should be created when 15 mol Na reacts with 15 mol Cl2 should be 877.5 g or 15 moles.

Calculation of the theoretical yield:

Since

Number of moles of Na = 15 mol

Number of moles of Cl₂ = 15 mol

The Chemical equation is

2Na + Cl₂      →     2NaCl

Now we have to compare the moles of Na and Cl₂ with NaCl.

So,

               Cl₂       :        NaCl

                1          :          2

              15          :         2/1×15 = 30 mol

               Na       :        NaCl

                2          :          2

              15          :          15

Now the mass should be

Mass = number of moles × molar mass

= 15 mol × 58.5 g/mol

= 877.5 g

Learn more about reaction here: https://brainly.com/question/11586370?referrer=searchResults

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