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If one wants 100g of Ag, how much ag2o is needed?

Sagot :

Mass Ag₂O needed = 107.416 g

Further explanation

Given

100 g Ag

Required

mass of Ag2O

Solution

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

mass of Ag in Ag2O :

= ((2 x Ar Ag)/molar mass Ag2O )x mass Ag2O

[tex]\tt mass~Ag=\dfrac{2.Ar~Ag}{MW~Ag_2O}\times mass~Ag_2O[/tex]

Ar Ag : 107,8682 g/mol

MW Ag₂O = 231,735 g/mol

Input the value :

mass Ag₂O=(mass Ag x MW Ag₂O) : (2 x Ar Ag)

mass Ag₂O = (100 g x 231,735 g/mol) : ( 2 x 107,8682 g/mol)

mass Ag₂O = 107.416 g