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Answer: 16.8L (at STP)
Explanation:
Mole P4O10 = 4*31+10*16 = 284
P4 = 124
moles P4O10 = 18.65/124 = 0.15
5 moles O2 per mole P4O10, so 5*0.15 moles O2 required = 0.75 moles
at STP 1 mole gas = 22.4 L
vol O2 = 0.75*22.4 = 16.8 L