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The sum of the digits in a two-digit number
is 12. The tens digit is 2 more than the
ones digit. Write and solve a system of
linear equations to find the number. Let x
répresent the tens digit, and let y represent
the ones digit.

Sagot :

Jackiezhang2007idn

Answer:

x+y=12 x-y=2 x=7, y=5

Step-by-step explanation:

you just set the equations up so that the sum is 12 difference is 2. then solve using eliminations, add the 2 equations which gives 2x=14, x=7 then solve for y. Hope this helped!!

A system of linear equations is a grouping of one or more linear equations with the same variables. The two-digit number is 75.

What is a system of linear equations?

A system of linear equations is a grouping of one or more linear equations with the same variables.

Let the tens digit be represented by x and the unit digit be represented by y.

Given that the sum of the digits in a two-digit number is 12. Therefore, the sum of the two digits can be written as

x + y = 12

x = 12 - y

Also, given that the tens digit is 2 more than the ones digit. Therefore, we can write,

x = y + 2

Equate the value of x from the two equations together,

x = x

12 - y = y + 2

12 - 2 = y + y

10 = 2y

y = 5

Substitute the value of y in the equation of x,

x = 12 - y

x = 7

Hence, the two-digit number is 75.

Learn more about Linear equations here:

https://brainly.com/question/11897796

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