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A miner finds a small minerallsragment with a volume of 11.5 cm3 and a mass of 57.4 g.
What is the density of the mineral fragment?
0.20 g/cm3
5.00 g/cm
5.74 g/cm
164 g/cm3

Sagot :

Cheribattle2idn

Answer:

Density = mass/ volume

Explanation:

57.4g / 11.5cm3 = 4.991304(g/cm)

round to sig figs = 5.00(g/cm)

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