Answered

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If the displacement of a horizontal mass-spring system was doubled, the elastic potential energy in the system would change by a factor of

Sagot :

Answer:

K'=4K

Explanation:

The electric potential energy is given by :

[tex]E=\dfrac{1}{2}kx^2[/tex]

Where

k is spring constant

x is compression or extension in the spring

If the displacement of a horizontal mass-spring system is doubled, x'= 2x

New elastic potential energy :

[tex]E'=\dfrac{1}{2}kx'^2\\\\E'=\dfrac{1}{2}k(2x)^2\\\\=\dfrac{1}{2}k\times 4x^2\\\\K'=4\times \dfrac{1}{2}kx^2\\\\K'=4K[/tex]

So, new elastic potential energy 4 times the initial elastic potential energy.

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